ENGINEERING TOOLS
Spring Calculators
Online design calculations for compression, extension, torsion, disc and leaf springs
Disc Spring Calculator
Inputs
Results
Stack: 1 parallel × 4 in series
Stress below yield and deflections within the recommended range.
Single-disc load–deflection
Per GB/T 1972—2005 (same as DIN 2092): F = 4E/(1−μ²)·t⁴/(K₁D²)·K₄²·(s/t)·[K₄²(h₀/t − s/t)(h₀/t − s/2t) + 1]; group 3 discs with contact flats use t′ and K₄. Negative stress = compression. For cyclic loading check the larger tensile stress of σII/σIII against fatigue diagrams. Friction in parallel stacks is ignored. For reference only.
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View related products →Formulas
Factor K₁
K₁ = (1/π)·((C−1)/C)² / ((C+1)/(C−1) − 2/ln C)
C = D/d; K₂, K₃ per GB/T 1972
Load
F = 4E/(1−μ²)·t⁴/(K₁D²)·(s/t)·[(h₀/t − s/t)(h₀/t − s/2t) + 1]
K₄ = 1 without flats; checked against all 87 standard sizes (≤ 2.1%)
σOM
−4E/(1−μ²)·t²/(K₁D²)·(s/t)·3/π
For static checks against yield
σI / σII
−4E/(1−μ²)·t²/(K₁D²)·(s/t)·[K₂(h₀/t − s/2t) ± K₃]
I upper inner (compr.), II lower inner (tension)
σIII / σIV
−4E/(1−μ²)·t²/(K₁D²)·(1/C)·(s/t)·[(K₂−2K₃)(h₀/t − s/2t) ∓ K₃]
III lower outer (tension), IV upper outer
Stacks
F = n·F₁, s = i·s₁, L₀ = i·[H₀ + (n−1)t]
n in parallel, i in series, no friction
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